This function uses signed integers for the unix_date and local variables -
if a negative number is supplied and the leap-year condition is not met,
month will be 0, leading to a read of day_n[-1]
Signed-off-by: Roel Kluin <[email protected]>
Signed-off-by: Andrew Morton <[email protected]>
Signed-off-by: Linus Torvalds <[email protected]>
month = 2;
} else {
nl_day = (year & 3) || day <= 59 ? day : day - 1;
- for (month = 0; month < 12; month++)
+ for (month = 1; month < 12; month++)
if (day_n[month] > nl_day)
break;
}