In two places, tmp is initialized implicitly by being passed as a
pointer during a function call. However, this is not obvious to the
compiler, which logs a warning.
Signed-off-by: Simon Que <[email protected]>
Acked-by: Peter Korsgaard <[email protected]>
Signed-off-by: David S. Miller <[email protected]>
dm_write_reg(dev, DM_SHARED_CTRL, phy ? 0xc : 0x4);
for (i = 0; i < DM_TIMEOUT; i++) {
- u8 tmp;
+ u8 tmp = 0;
udelay(1);
ret = dm_read_reg(dev, DM_SHARED_CTRL, &tmp);
dm_write_reg(dev, DM_SHARED_CTRL, phy ? 0x1a : 0x12);
for (i = 0; i < DM_TIMEOUT; i++) {
- u8 tmp;
+ u8 tmp = 0;
udelay(1);
ret = dm_read_reg(dev, DM_SHARED_CTRL, &tmp);